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239994000041 is a prime number
BaseRepresentation
bin1101111110000011000…
…0011101001010101001
3211221110121001101121012
43133200300131022221
512413001431000131
6302130212153305
723224163225135
oct3374060351251
9757417041535
10239994000041
11928653a13a4
123a619608835
1319829080763
14b88996a3c5
15639967352b
hex37e0c1d2a9

239994000041 has 2 divisors, whose sum is σ = 239994000042. Its totient is φ = 239994000040.

The previous prime is 239994000031. The next prime is 239994000049. The reversal of 239994000041 is 140000499932.

239994000041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 218766675625 + 21227324416 = 467725^2 + 145696^2 .

It is a cyclic number.

It is not a de Polignac number, because 239994000041 - 210 = 239993999017 is a prime.

It is not a weakly prime, because it can be changed into another prime (239994000049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 119997000020 + 119997000021.

It is an arithmetic number, because the mean of its divisors is an integer number (119997000021).

Almost surely, 2239994000041 is an apocalyptic number.

It is an amenable number.

239994000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

239994000041 is an equidigital number, since it uses as much as digits as its factorization.

239994000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 41.

Adding to 239994000041 its reverse (140000499932), we get a palindrome (379994499973).

The spelling of 239994000041 in words is "two hundred thirty-nine billion, nine hundred ninety-four million, forty-one", and thus it is an aban number.