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240045103334051 is a prime number
BaseRepresentation
bin110110100101000111011011…
…000111010100001010100011
31011110221002100222102211121122
4312211013123013110022203
5222430344332423142201
62210311110442442455
7101363454302366141
oct6645073307241243
91143832328384548
10240045103334051
116a538613961904
1222b0a42350342b
13a3c3204ca7992
14433c36038a591
151cb41cd80be1b
hexda51db1d42a3

240045103334051 has 2 divisors, whose sum is σ = 240045103334052. Its totient is φ = 240045103334050.

The previous prime is 240045103334033. The next prime is 240045103334077. The reversal of 240045103334051 is 150433301540042.

240045103334051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 240045103334051 - 234 = 240027923464867 is a prime.

It is not a weakly prime, because it can be changed into another prime (240045103334551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120022551667025 + 120022551667026.

It is an arithmetic number, because the mean of its divisors is an integer number (120022551667026).

Almost surely, 2240045103334051 is an apocalyptic number.

240045103334051 is a deficient number, since it is larger than the sum of its proper divisors (1).

240045103334051 is an equidigital number, since it uses as much as digits as its factorization.

240045103334051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 240045103334051 its reverse (150433301540042), we get a palindrome (390478404874093).

The spelling of 240045103334051 in words is "two hundred forty trillion, forty-five billion, one hundred three million, three hundred thirty-four thousand, fifty-one".