Base | Representation |
---|---|
bin | 110110101000111000100101… |
… | …000011111110110110001011 |
3 | 1011111211211201212020120202202 |
4 | 312220320211003332312023 |
5 | 222444120134223341133 |
6 | 2211030053005150415 |
7 | 101421252115005452 |
oct | 6650704503766613 |
9 | 1144754655216682 |
10 | 240304042012043 |
11 | 6a628410003139 |
12 | 22b5064955b40b |
13 | a41175cbc6239 |
14 | 434aac5dadb99 |
15 | 1cbacd623d2e8 |
hex | da8e250fed8b |
240304042012043 has 2 divisors, whose sum is σ = 240304042012044. Its totient is φ = 240304042012042.
The previous prime is 240304042011989. The next prime is 240304042012081. The reversal of 240304042012043 is 340210240403042.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-240304042012043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 240304042011997 and 240304042012015.
It is not a weakly prime, because it can be changed into another prime (240304042512043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120152021006021 + 120152021006022.
It is an arithmetic number, because the mean of its divisors is an integer number (120152021006022).
Almost surely, 2240304042012043 is an apocalyptic number.
240304042012043 is a deficient number, since it is larger than the sum of its proper divisors (1).
240304042012043 is an equidigital number, since it uses as much as digits as its factorization.
240304042012043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 29.
Adding to 240304042012043 its reverse (340210240403042), we get a palindrome (580514282415085).
The spelling of 240304042012043 in words is "two hundred forty trillion, three hundred four billion, forty-two million, twelve thousand, forty-three".
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