Search a number
-
+
2404113 = 3801371
BaseRepresentation
bin1001001010111100010001
311112010211020
421022330101
51103412423
6123310053
726302035
oct11127421
94463736
102404113
1113a2278
1297b329
1366236a
144681c5
153274e3
hex24af11

2404113 has 4 divisors (see below), whose sum is σ = 3205488. Its totient is φ = 1602740.

The previous prime is 2404111. The next prime is 2404139. The reversal of 2404113 is 3114042.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2404113 - 21 = 2404111 is a prime.

It is a D-number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2404092 and 2404101.

It is not an unprimeable number, because it can be changed into a prime (2404111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 400683 + ... + 400688.

It is an arithmetic number, because the mean of its divisors is an integer number (801372).

22404113 is an apocalyptic number.

It is an amenable number.

2404113 is a deficient number, since it is larger than the sum of its proper divisors (801375).

2404113 is an equidigital number, since it uses as much as digits as its factorization.

2404113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 801374.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 2404113 is about 1550.5202352759. The cubic root of 2404113 is about 133.9630290818.

Adding to 2404113 its reverse (3114042), we get a palindrome (5518155).

The spelling of 2404113 in words is "two million, four hundred four thousand, one hundred thirteen".

Divisors: 1 3 801371 2404113