240653777414131 has 2 divisors, whose sum is σ = 240653777414132. Its totient is φ = 240653777414130.

The previous prime is 240653777414059. The next prime is 240653777414191. The reversal of 240653777414131 is 131414777356042.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 240653777414131 - 2¹³ = 240653777405939 is a prime.

It is a super-2 number, since 2×240653777414131² (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (240653777414191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120326888707065 + 120326888707066.

It is an arithmetic number, because the mean of its divisors is an integer number (120326888707066).

Almost surely, 2^{240653777414131} is an apocalyptic number.

240653777414131 is a deficient number, since it is larger than the sum of its proper divisors (1).

240653777414131 is an equidigital number, since it uses as much as digits as its factorization.

240653777414131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11854080, while the sum is 55.

The spelling of 240653777414131 in words is "two hundred forty trillion, six hundred fifty-three billion, seven hundred seventy-seven million, four hundred fourteen thousand, one hundred thirty-one".