Base | Representation |
---|---|
bin | 110110110011101000001110… |
… | …101101001110010000010011 |
3 | 1011121110102120101112211101101 |
4 | 312303220032231032100103 |
5 | 223043214314214301003 |
6 | 2212353203411445231 |
7 | 101525511260412061 |
oct | 6663501655162023 |
9 | 1147412511484341 |
10 | 241042401322003 |
11 | 6a892565647096 |
12 | 2304b7705b6817 |
13 | a46627c534008 |
14 | 437472b9d9031 |
15 | 1cd00ecc4211d |
hex | db3a0eb4e413 |
241042401322003 has 2 divisors, whose sum is σ = 241042401322004. Its totient is φ = 241042401322002.
The previous prime is 241042401321949. The next prime is 241042401322049. The reversal of 241042401322003 is 300223104240142.
241042401322003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241042401322003 - 237 = 240904962368531 is a prime.
It is not a weakly prime, because it can be changed into another prime (241042405322003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120521200661001 + 120521200661002.
It is an arithmetic number, because the mean of its divisors is an integer number (120521200661002).
Almost surely, 2241042401322003 is an apocalyptic number.
241042401322003 is a deficient number, since it is larger than the sum of its proper divisors (1).
241042401322003 is an equidigital number, since it uses as much as digits as its factorization.
241042401322003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 241042401322003 its reverse (300223104240142), we get a palindrome (541265505562145).
The spelling of 241042401322003 in words is "two hundred forty-one trillion, forty-two billion, four hundred one million, three hundred twenty-two thousand, three".
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