Base | Representation |
---|---|
bin | 1010111101110010001001… |
… | …10100100101001110100001 |
3 | 10011101012010110201001102221 |
4 | 11132321010310211032201 |
5 | 11130032112331100101 |
6 | 123141223343511041 |
7 | 5036054056662061 |
oct | 536710464451641 |
9 | 104335113631387 |
10 | 24113101034401 |
11 | 77573439a7865 |
12 | 28553448b8481 |
13 | 105bb17ba7162 |
14 | 5d511a5673a1 |
15 | 2bc3852d8aa1 |
hex | 15ee44d253a1 |
24113101034401 has 2 divisors, whose sum is σ = 24113101034402. Its totient is φ = 24113101034400.
The previous prime is 24113101034389. The next prime is 24113101034417. The reversal of 24113101034401 is 10443010131142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14069430853776 + 10043670180625 = 3750924^2 + 3169175^2 .
It is a cyclic number.
It is not a de Polignac number, because 24113101034401 - 25 = 24113101034369 is a prime.
It is not a weakly prime, because it can be changed into another prime (24113101034441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12056550517200 + 12056550517201.
It is an arithmetic number, because the mean of its divisors is an integer number (12056550517201).
Almost surely, 224113101034401 is an apocalyptic number.
It is an amenable number.
24113101034401 is a deficient number, since it is larger than the sum of its proper divisors (1).
24113101034401 is an equidigital number, since it uses as much as digits as its factorization.
24113101034401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 24113101034401 its reverse (10443010131142), we get a palindrome (34556111165543).
The spelling of 24113101034401 in words is "twenty-four trillion, one hundred thirteen billion, one hundred one million, thirty-four thousand, four hundred one".
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