Base | Representation |
---|---|
bin | 110110110101000111001000… |
… | …010110001101011101101001 |
3 | 1011121211011120220002001121002 |
4 | 312311013020112031131221 |
5 | 223101402011311140213 |
6 | 2212512055004124345 |
7 | 101536046361625613 |
oct | 6665071026153551 |
9 | 1147734526061532 |
10 | 241144300099433 |
11 | 6a9217a5872835 |
12 | 2306746a2366b5 |
13 | a472a6b5399a3 |
14 | 4379636cc5db3 |
15 | 1cd2ab39e7658 |
hex | db51c858d769 |
241144300099433 has 2 divisors, whose sum is σ = 241144300099434. Its totient is φ = 241144300099432.
The previous prime is 241144300099427. The next prime is 241144300099453. The reversal of 241144300099433 is 334990003441142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 240431167140649 + 713132958784 = 15505843^2 + 844472^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241144300099433 is a prime.
It is not a weakly prime, because it can be changed into another prime (241144300099453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120572150049716 + 120572150049717.
It is an arithmetic number, because the mean of its divisors is an integer number (120572150049717).
Almost surely, 2241144300099433 is an apocalyptic number.
It is an amenable number.
241144300099433 is a deficient number, since it is larger than the sum of its proper divisors (1).
241144300099433 is an equidigital number, since it uses as much as digits as its factorization.
241144300099433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1119744, while the sum is 47.
The spelling of 241144300099433 in words is "two hundred forty-one trillion, one hundred forty-four billion, three hundred million, ninety-nine thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •