2412143113 has 4 divisors (see below), whose sum is σ = 2412253440. Its totient is φ = 2412032788.

The previous prime is 2412143089. The next prime is 2412143159. The reversal of 2412143113 is 3113412142.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3113412142 = 2 ⋅1556706071.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2412143113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2412140113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10093 + ... + 70186.

It is an arithmetic number, because the mean of its divisors is an integer number (603063360).

Almost surely, 2^2412143113 is an apocalyptic number.

It is an amenable number.

2412143113 is a deficient number, since it is larger than the sum of its proper divisors (110327).

2412143113 is an equidigital number, since it uses as much as digits as its factorization.

2412143113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110326.

The product of its digits is 576, while the sum is 22.

The square root of 2412143113 is about 49113.5736125972. The cubic root of 2412143113 is about 1341.1201580684.

Adding to 2412143113 its reverse (3113412142), we get a palindrome (5525555255).

The spelling of 2412143113 in words is "two billion, four hundred twelve million, one hundred forty-three thousand, one hundred thirteen".