Base | Representation |
---|---|
bin | 110110110110001110111101… |
… | …110101011000000101010111 |
3 | 1011122002112200102111001202000 |
4 | 312312032331311120011113 |
5 | 223104132443340200401 |
6 | 2213011332504450343 |
7 | 101544446661603651 |
oct | 6666167565300527 |
9 | 1148075612431660 |
10 | 241221433131351 |
11 | 6a951487411302 |
12 | 2307a3b5a799b3 |
13 | a47a1116c7a8a |
14 | 437d272da76d1 |
15 | 1cd4aca44e186 |
hex | db63bdd58157 |
241221433131351 has 16 divisors (see below), whose sum is σ = 362398397195520. Its totient is φ = 158549298770520.
The previous prime is 241221433131337. The next prime is 241221433131379. The reversal of 241221433131351 is 153131334122142.
241221433131351 is a `hidden beast` number, since 2 + 4 + 1 + 2 + 2 + 1 + 4 + 331 + 313 + 5 + 1 = 666.
It is not a de Polignac number, because 241221433131351 - 25 = 241221433131319 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (241221433031351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62916386485 + ... + 62916390318.
It is an arithmetic number, because the mean of its divisors is an integer number (22649899824720).
Almost surely, 2241221433131351 is an apocalyptic number.
241221433131351 is a deficient number, since it is larger than the sum of its proper divisors (121176964064169).
241221433131351 is a wasteful number, since it uses less digits than its factorization.
241221433131351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125832776883 (or 125832776877 counting only the distinct ones).
The product of its digits is 51840, while the sum is 36.
Adding to 241221433131351 its reverse (153131334122142), we get a palindrome (394352767253493).
The spelling of 241221433131351 in words is "two hundred forty-one trillion, two hundred twenty-one billion, four hundred thirty-three million, one hundred thirty-one thousand, three hundred fifty-one".
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