Base | Representation |
---|---|
bin | 110110110110001111110100… |
… | …100110101000001111011011 |
3 | 1011122002122001110112001100221 |
4 | 312312033310212220033123 |
5 | 223104141334103343001 |
6 | 2213012004011340511 |
7 | 101544511520141011 |
oct | 6666176446501733 |
9 | 1148078043461327 |
10 | 241222352012251 |
11 | 6a95190906a105 |
12 | 2307a611751737 |
13 | a47a229ba239c |
14 | 437d31d03a8b1 |
15 | 1cd4b30e5a1a1 |
hex | db63f49a83db |
241222352012251 has 2 divisors, whose sum is σ = 241222352012252. Its totient is φ = 241222352012250.
The previous prime is 241222352012207. The next prime is 241222352012261. The reversal of 241222352012251 is 152210253222142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241222352012251 - 211 = 241222352010203 is a prime.
It is a super-3 number, since 3×2412223520122513 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (241222352012261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120611176006125 + 120611176006126.
It is an arithmetic number, because the mean of its divisors is an integer number (120611176006126).
Almost surely, 2241222352012251 is an apocalyptic number.
241222352012251 is a deficient number, since it is larger than the sum of its proper divisors (1).
241222352012251 is an equidigital number, since it uses as much as digits as its factorization.
241222352012251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38400, while the sum is 34.
The spelling of 241222352012251 in words is "two hundred forty-one trillion, two hundred twenty-two billion, three hundred fifty-two million, twelve thousand, two hundred fifty-one".
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