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2413401218441 is a prime number
BaseRepresentation
bin100011000111101001111…
…011000001110110001001
322112201102002011122122122
4203013221323001312021
5304020121202442231
65044411243501025
7336235221611543
oct43075173016611
98481362148578
102413401218441
11850577085a24
1232b897227775
13146776421465
1484b487bc693
1542ba117c77b
hex231e9ec1d89

2413401218441 has 2 divisors, whose sum is σ = 2413401218442. Its totient is φ = 2413401218440.

The previous prime is 2413401218413. The next prime is 2413401218453. The reversal of 2413401218441 is 1448121043142.

2413401218441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1654899572041 + 758501646400 = 1286429^2 + 870920^2 .

It is a cyclic number.

It is not a de Polignac number, because 2413401218441 - 26 = 2413401218377 is a prime.

It is not a weakly prime, because it can be changed into another prime (2413401238441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206700609220 + 1206700609221.

It is an arithmetic number, because the mean of its divisors is an integer number (1206700609221).

Almost surely, 22413401218441 is an apocalyptic number.

It is an amenable number.

2413401218441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2413401218441 is an equidigital number, since it uses as much as digits as its factorization.

2413401218441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24576, while the sum is 35.

The spelling of 2413401218441 in words is "two trillion, four hundred thirteen billion, four hundred one million, two hundred eighteen thousand, four hundred forty-one".