2413410500113 has 4 divisors (see below), whose sum is σ = 2413628505088. Its totient is φ = 2413192495140.

The previous prime is 2413410500093. The next prime is 2413410500117. The reversal of 2413410500113 is 3110050143142.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2413410500113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2413410500117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108985881 + ... + 109008022.

It is an arithmetic number, because the mean of its divisors is an integer number (603407126272).

Almost surely, 2^{2413410500113} is an apocalyptic number.

It is an amenable number.

2413410500113 is a deficient number, since it is larger than the sum of its proper divisors (218004975).

2413410500113 is a wasteful number, since it uses less digits than its factorization.

2413410500113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 218004974.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 2413410500113 its reverse (3110050143142), we get a palindrome (5523460643255).

The spelling of 2413410500113 in words is "two trillion, four hundred thirteen billion, four hundred ten million, five hundred thousand, one hundred thirteen".