241343310013132 has 6 divisors (see below), whose sum is σ = 422350792522988. Its totient is φ = 120671655006564.

The previous prime is 241343310012997. The next prime is 241343310013139. The reversal of 241343310013132 is 231310013343142.

It is a junction number, because it is equal to n+sod(n) for n = 241343310013094 and 241343310013103.

It is not an unprimeable number, because it can be changed into a prime (241343310013139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30167913751638 + ... + 30167913751645.

Almost surely, 2^{241343310013132} is an apocalyptic number.

It is an amenable number.

241343310013132 is a deficient number, since it is larger than the sum of its proper divisors (181007482509856).

241343310013132 is a wasteful number, since it uses less digits than its factorization.

241343310013132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60335827503287 (or 60335827503285 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 241343310013132 its reverse (231310013343142), we get a palindrome (472653323356274).

The spelling of 241343310013132 in words is "two hundred forty-one trillion, three hundred forty-three billion, three hundred ten million, thirteen thousand, one hundred thirty-two".