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24140121342419 is a prime number
BaseRepresentation
bin1010111110100100011110…
…10110111000000111010011
310011110202212120011220211202
411133102033112320013103
511131002432030424134
6123201452454501415
75041031465546225
oct537221726700723
9104422776156752
1024140121342419
11776784a191135
12285a62596486b
131061532b483b4
145d6560d74415
152bce17530d7e
hex15f48f5b81d3

24140121342419 has 2 divisors, whose sum is σ = 24140121342420. Its totient is φ = 24140121342418.

The previous prime is 24140121342391. The next prime is 24140121342511. The reversal of 24140121342419 is 91424312104142.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 24140121342419 - 228 = 24139852906963 is a prime.

It is a super-3 number, since 3×241401213424193 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (24140121342119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12070060671209 + 12070060671210.

It is an arithmetic number, because the mean of its divisors is an integer number (12070060671210).

Almost surely, 224140121342419 is an apocalyptic number.

24140121342419 is a deficient number, since it is larger than the sum of its proper divisors (1).

24140121342419 is an equidigital number, since it uses as much as digits as its factorization.

24140121342419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 38.

The spelling of 24140121342419 in words is "twenty-four trillion, one hundred forty billion, one hundred twenty-one million, three hundred forty-two thousand, four hundred nineteen".