Base | Representation |
---|---|
bin | 110110111000111001011001… |
… | …111101110101110100000011 |
3 | 1011122202001001120111100011101 |
4 | 312320321121331311310003 |
5 | 223120132243423104103 |
6 | 2213231400323155231 |
7 | 101563616044655554 |
oct | 6670713175656403 |
9 | 1148661046440141 |
10 | 241404441222403 |
11 | 6aa1205973a848 |
12 | 230a996ab15b17 |
13 | a4914585c7554 |
14 | 43880744b432b |
15 | 1cd973bc98a1d |
hex | db8e59f75d03 |
241404441222403 has 2 divisors, whose sum is σ = 241404441222404. Its totient is φ = 241404441222402.
The previous prime is 241404441222383. The next prime is 241404441222407. The reversal of 241404441222403 is 304222144404142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241404441222403 - 237 = 241267002268931 is a prime.
It is a super-2 number, since 2×2414044412224032 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (241404441222407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120702220611201 + 120702220611202.
It is an arithmetic number, because the mean of its divisors is an integer number (120702220611202).
Almost surely, 2241404441222403 is an apocalyptic number.
241404441222403 is a deficient number, since it is larger than the sum of its proper divisors (1).
241404441222403 is an equidigital number, since it uses as much as digits as its factorization.
241404441222403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 196608, while the sum is 37.
Adding to 241404441222403 its reverse (304222144404142), we get a palindrome (545626585626545).
The spelling of 241404441222403 in words is "two hundred forty-one trillion, four hundred four billion, four hundred forty-one million, two hundred twenty-two thousand, four hundred three".
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