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241430345113 = 2003359333547
BaseRepresentation
bin1110000011011001011…
…1101011010110011001
3212002011200210021121211
43200312113223112121
512423422132020423
6302524522103121
723304604034116
oct3406627532631
9762150707554
10241430345113
1193432154741
123a95a64aaa1
13199c7816299
14b98461d90d
1564307e710d
hex38365eb599

241430345113 has 8 divisors (see below), whose sum is σ = 241625310048. Its totient is φ = 241235458464.

The previous prime is 241430345083. The next prime is 241430345161. The reversal of 241430345113 is 311543034142.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 241430345113 - 25 = 241430345081 is a prime.

It is a super-2 number, since 2×2414303451132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (241430345813) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7180006 + ... + 7213552.

It is an arithmetic number, because the mean of its divisors is an integer number (30203163756).

Almost surely, 2241430345113 is an apocalyptic number.

It is an amenable number.

241430345113 is a deficient number, since it is larger than the sum of its proper divisors (194964935).

241430345113 is a wasteful number, since it uses less digits than its factorization.

241430345113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39143.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 241430345113 its reverse (311543034142), we get a palindrome (552973379255).

The spelling of 241430345113 in words is "two hundred forty-one billion, four hundred thirty million, three hundred forty-five thousand, one hundred thirteen".

Divisors: 1 2003 3593 33547 7196779 67194641 120534371 241430345113