Base | Representation |
---|---|
bin | 100011001000100101101… |
… | …101111000011101111001 |
3 | 22112210222222211211001120 |
4 | 203020211231320131321 |
5 | 304024200011430423 |
6 | 5045055001335453 |
7 | 336302122554201 |
oct | 43104555703571 |
9 | 8483888754046 |
10 | 2414404405113 |
11 | 850a41385a18 |
12 | 32bb17197589 |
13 | 1468a6205c3c |
14 | 84c01b19401 |
15 | 42c0e28cee3 |
hex | 23225b78779 |
2414404405113 has 8 divisors (see below), whose sum is σ = 3219281222976. Its totient is φ = 1609565262000.
The previous prime is 2414404405097. The next prime is 2414404405123. The reversal of 2414404405113 is 3115044044142.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2414404405113 - 24 = 2414404405097 is a prime.
It is a super-3 number, since 3×24144044051133 (a number of 38 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (2414404405123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9268813 + ... + 9525738.
It is an arithmetic number, because the mean of its divisors is an integer number (402410152872).
Almost surely, 22414404405113 is an apocalyptic number.
It is an amenable number.
2414404405113 is a deficient number, since it is larger than the sum of its proper divisors (804876817863).
2414404405113 is a wasteful number, since it uses less digits than its factorization.
2414404405113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18837375.
The product of its (nonzero) digits is 30720, while the sum is 33.
Adding to 2414404405113 its reverse (3115044044142), we get a palindrome (5529448449255).
The spelling of 2414404405113 in words is "two trillion, four hundred fourteen billion, four hundred four million, four hundred five thousand, one hundred thirteen".
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