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2414404405113 = 34282118794551
BaseRepresentation
bin100011001000100101101…
…101111000011101111001
322112210222222211211001120
4203020211231320131321
5304024200011430423
65045055001335453
7336302122554201
oct43104555703571
98483888754046
102414404405113
11850a41385a18
1232bb17197589
131468a6205c3c
1484c01b19401
1542c0e28cee3
hex23225b78779

2414404405113 has 8 divisors (see below), whose sum is σ = 3219281222976. Its totient is φ = 1609565262000.

The previous prime is 2414404405097. The next prime is 2414404405123. The reversal of 2414404405113 is 3115044044142.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2414404405113 - 24 = 2414404405097 is a prime.

It is a super-3 number, since 3×24144044051133 (a number of 38 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (2414404405123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9268813 + ... + 9525738.

It is an arithmetic number, because the mean of its divisors is an integer number (402410152872).

Almost surely, 22414404405113 is an apocalyptic number.

It is an amenable number.

2414404405113 is a deficient number, since it is larger than the sum of its proper divisors (804876817863).

2414404405113 is a wasteful number, since it uses less digits than its factorization.

2414404405113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18837375.

The product of its (nonzero) digits is 30720, while the sum is 33.

Adding to 2414404405113 its reverse (3115044044142), we get a palindrome (5529448449255).

The spelling of 2414404405113 in words is "two trillion, four hundred fourteen billion, four hundred four million, four hundred five thousand, one hundred thirteen".

Divisors: 1 3 42821 128463 18794551 56383653 804801468371 2414404405113