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24145515121139 is a prime number
BaseRepresentation
bin1010111110101110100001…
…10110100000100111110011
310011111021210110112021020222
411133113100312200213303
511131100003332334024
6123204144014123255
75041312242114506
oct537272066404763
9104437713467228
1024145515121139
11776a0678a49a5
12285b6901b052b
131061bb244a939
145d691345b13d
152bd130d1c85e
hex15f5d0da09f3

24145515121139 has 2 divisors, whose sum is σ = 24145515121140. Its totient is φ = 24145515121138.

The previous prime is 24145515121121. The next prime is 24145515121219. The reversal of 24145515121139 is 93112151554142.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-24145515121139 is a prime.

It is a super-3 number, since 3×241455151211393 (a number of 41 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 24145515121139.

It is not a weakly prime, because it can be changed into another prime (24145515121109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12072757560569 + 12072757560570.

It is an arithmetic number, because the mean of its divisors is an integer number (12072757560570).

Almost surely, 224145515121139 is an apocalyptic number.

24145515121139 is a deficient number, since it is larger than the sum of its proper divisors (1).

24145515121139 is an equidigital number, since it uses as much as digits as its factorization.

24145515121139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 216000, while the sum is 44.

The spelling of 24145515121139 in words is "twenty-four trillion, one hundred forty-five billion, five hundred fifteen million, one hundred twenty-one thousand, one hundred thirty-nine".