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2415403000113 = 316931747727211
BaseRepresentation
bin100011001001100001001…
…111001110000100110001
322112220120120212200212120
4203021201033032010301
5304033221132000423
65045342032544453
7336335636513655
oct43114117160461
98486516780776
102415403000113
1185140402a144
123301556b2129
13146a0507075c
1484c985bca65
1542c6bc92ee3
hex232613ce131

2415403000113 has 16 divisors (see below), whose sum is σ = 3222742412736. Its totient is φ = 1609166312640.

The previous prime is 2415403000097. The next prime is 2415403000133. The reversal of 2415403000113 is 3110003045142.

It is a happy number.

It is not a de Polignac number, because 2415403000113 - 24 = 2415403000097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2415403000133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 88752078 + ... + 88779288.

It is an arithmetic number, because the mean of its divisors is an integer number (201421400796).

Almost surely, 22415403000113 is an apocalyptic number.

It is an amenable number.

2415403000113 is a deficient number, since it is larger than the sum of its proper divisors (807339412623).

2415403000113 is a wasteful number, since it uses less digits than its factorization.

2415403000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46384.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 2415403000113 its reverse (3110003045142), we get a palindrome (5525406045255).

The spelling of 2415403000113 in words is "two trillion, four hundred fifteen billion, four hundred three million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 1693 5079 17477 27211 52431 81633 29588561 46068223 88765683 138204669 475566647 1426699941 805134333371 2415403000113