Base | Representation |
---|---|
bin | 1011000000011000001011… |
… | …11111000100101001000001 |
3 | 10011200201012210112020202201 |
4 | 11200030011333010221001 |
5 | 11133012142212224441 |
6 | 123250204525313201 |
7 | 5045361045215602 |
oct | 540140577045101 |
9 | 104621183466681 |
10 | 24202241133121 |
11 | 7791127194337 |
12 | 286a681705801 |
13 | 10673528024bc |
14 | 5d9575185da9 |
15 | 2be850e09c31 |
hex | 160305fc4a41 |
24202241133121 has 2 divisors, whose sum is σ = 24202241133122. Its totient is φ = 24202241133120.
The previous prime is 24202241133113. The next prime is 24202241133127. The reversal of 24202241133121 is 12133114220242.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22578757427521 + 1623483705600 = 4751711^2 + 1274160^2 .
It is a cyclic number.
It is not a de Polignac number, because 24202241133121 - 23 = 24202241133113 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 24202241133121.
It is not a weakly prime, because it can be changed into another prime (24202241133127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12101120566560 + 12101120566561.
It is an arithmetic number, because the mean of its divisors is an integer number (12101120566561).
Almost surely, 224202241133121 is an apocalyptic number.
It is an amenable number.
24202241133121 is a deficient number, since it is larger than the sum of its proper divisors (1).
24202241133121 is an equidigital number, since it uses as much as digits as its factorization.
24202241133121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 24202241133121 its reverse (12133114220242), we get a palindrome (36335355353363).
The spelling of 24202241133121 in words is "twenty-four trillion, two hundred two billion, two hundred forty-one million, one hundred thirty-three thousand, one hundred twenty-one".
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