Base | Representation |
---|---|
bin | 10110100011000101… |
… | …101000101101000011 |
3 | 2022111022021020110120 |
4 | 112203011220231003 |
5 | 344041004001011 |
6 | 15042233431323 |
7 | 1514654051133 |
oct | 264305505503 |
9 | 68438236416 |
10 | 24211000131 |
11 | a2a452981a |
12 | 483826b543 |
13 | 238ac354a6 |
14 | 1259682ac3 |
15 | 96a7bea06 |
hex | 5a3168b43 |
24211000131 has 4 divisors (see below), whose sum is σ = 32281333512. Its totient is φ = 16140666752.
The previous prime is 24211000129. The next prime is 24211000141. The reversal of 24211000131 is 13100011242.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 24211000131 - 21 = 24211000129 is a prime.
It is a super-2 number, since 2×242110001312 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 24211000131.
It is not an unprimeable number, because it can be changed into a prime (24211000141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4035166686 + ... + 4035166691.
It is an arithmetic number, because the mean of its divisors is an integer number (8070333378).
Almost surely, 224211000131 is an apocalyptic number.
24211000131 is a deficient number, since it is larger than the sum of its proper divisors (8070333381).
24211000131 is an equidigital number, since it uses as much as digits as its factorization.
24211000131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8070333380.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 24211000131 its reverse (13100011242), we get a palindrome (37311011373).
The spelling of 24211000131 in words is "twenty-four billion, two hundred eleven million, one hundred thirty-one", and thus it is an aban number.
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