Base | Representation |
---|---|
bin | 110111000110001000110010… |
… | …111110011011000010000001 |
3 | 1011202222000121121011221012211 |
4 | 313012020302332123002001 |
5 | 223230034211423131202 |
6 | 2215205354550022121 |
7 | 102016426513040521 |
oct | 6706106276330201 |
9 | 1152860547157184 |
10 | 242314320130177 |
11 | 70232a20657229 |
12 | 2321617b647941 |
13 | a5291b09539c9 |
14 | 43ba10b8db681 |
15 | 1d032417141d7 |
hex | dc6232f9b081 |
242314320130177 has 2 divisors, whose sum is σ = 242314320130178. Its totient is φ = 242314320130176.
The previous prime is 242314320130117. The next prime is 242314320130187. The reversal of 242314320130177 is 771031023413242.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 138531934861681 + 103782385268496 = 11769959^2 + 10187364^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-242314320130177 is a prime.
It is not a weakly prime, because it can be changed into another prime (242314320130117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121157160065088 + 121157160065089.
It is an arithmetic number, because the mean of its divisors is an integer number (121157160065089).
Almost surely, 2242314320130177 is an apocalyptic number.
It is an amenable number.
242314320130177 is a deficient number, since it is larger than the sum of its proper divisors (1).
242314320130177 is an equidigital number, since it uses as much as digits as its factorization.
242314320130177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 169344, while the sum is 40.
The spelling of 242314320130177 in words is "two hundred forty-two trillion, three hundred fourteen billion, three hundred twenty million, one hundred thirty thousand, one hundred seventy-seven".
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