Base | Representation |
---|---|
bin | 1110000111000000110… |
… | …0001010001010100011 |
3 | 212011200022010101102121 |
4 | 3201300030022022203 |
5 | 12432414000413011 |
6 | 303205053525111 |
7 | 23340623303404 |
oct | 3416014121243 |
9 | 764608111377 |
10 | 242400404131 |
11 | 9388a788406 |
12 | 3ab8b4a3797 |
13 | 19b2079c2c2 |
14 | ba373b59ab |
15 | 648aa61e71 |
hex | 387030a2a3 |
242400404131 has 2 divisors, whose sum is σ = 242400404132. Its totient is φ = 242400404130.
The previous prime is 242400404123. The next prime is 242400404153. The reversal of 242400404131 is 131404004242.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 242400404131 - 23 = 242400404123 is a prime.
It is a super-2 number, since 2×2424004041312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 242400404096 and 242400404105.
It is not a weakly prime, because it can be changed into another prime (242400404431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121200202065 + 121200202066.
It is an arithmetic number, because the mean of its divisors is an integer number (121200202066).
Almost surely, 2242400404131 is an apocalyptic number.
242400404131 is a deficient number, since it is larger than the sum of its proper divisors (1).
242400404131 is an equidigital number, since it uses as much as digits as its factorization.
242400404131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 242400404131 its reverse (131404004242), we get a palindrome (373804408373).
The spelling of 242400404131 in words is "two hundred forty-two billion, four hundred million, four hundred four thousand, one hundred thirty-one".
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