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242512302433 is a prime number
BaseRepresentation
bin1110000111011011011…
…1000001000101100001
3212011222002200102001011
43201312313001011201
512433131122134213
6303224132140521
723343452362462
oct3416667010541
9764862612034
10242512302433
1193937966245
123b000a67741
1319b3aa1a70b
14ba481c2d69
1564957b703d
hex3876dc1161

242512302433 has 2 divisors, whose sum is σ = 242512302434. Its totient is φ = 242512302432.

The previous prime is 242512302349. The next prime is 242512302437. The reversal of 242512302433 is 334203215242.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 242485335184 + 26967249 = 492428^2 + 5193^2 .

It is a cyclic number.

It is not a de Polignac number, because 242512302433 - 217 = 242512171361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 242512302395 and 242512302404.

It is not a weakly prime, because it can be changed into another prime (242512302437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121256151216 + 121256151217.

It is an arithmetic number, because the mean of its divisors is an integer number (121256151217).

Almost surely, 2242512302433 is an apocalyptic number.

It is an amenable number.

242512302433 is a deficient number, since it is larger than the sum of its proper divisors (1).

242512302433 is an equidigital number, since it uses as much as digits as its factorization.

242512302433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 242512302433 its reverse (334203215242), we get a palindrome (576715517675).

The spelling of 242512302433 in words is "two hundred forty-two billion, five hundred twelve million, three hundred two thousand, four hundred thirty-three".