Base | Representation |
---|---|
bin | 110111001001010011000011… |
… | …111110011101101011100011 |
3 | 1011210201210012022200111200010 |
4 | 313021103003332131223203 |
5 | 223242114003301432042 |
6 | 2215453233350100003 |
7 | 102041215456510413 |
oct | 6711230376355343 |
9 | 1153653168614603 |
10 | 242531501202147 |
11 | 70307039711063 |
12 | 2325029104a603 |
13 | a543812624051 |
14 | 43c6831754643 |
15 | 1d08c031cb59c |
hex | dc94c3f9dae3 |
242531501202147 has 8 divisors (see below), whose sum is σ = 324125625738240. Its totient is φ = 161312522067080.
The previous prime is 242531501202121. The next prime is 242531501202181. The reversal of 242531501202147 is 741202105135242.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 242531501202147 - 215 = 242531501169379 is a prime.
It is not an unprimeable number, because it can be changed into a prime (242531501202247) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 93786348747 + ... + 93786351332.
It is an arithmetic number, because the mean of its divisors is an integer number (40515703217280).
Almost surely, 2242531501202147 is an apocalyptic number.
242531501202147 is a deficient number, since it is larger than the sum of its proper divisors (81594124536093).
242531501202147 is a wasteful number, since it uses less digits than its factorization.
242531501202147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187572700513.
The product of its (nonzero) digits is 134400, while the sum is 39.
Adding to 242531501202147 its reverse (741202105135242), we get a palindrome (983733606337389).
The spelling of 242531501202147 in words is "two hundred forty-two trillion, five hundred thirty-one billion, five hundred one million, two hundred two thousand, one hundred forty-seven".
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