Base | Representation |
---|---|
bin | 100011010111000111010… |
… | …110101000011101111011 |
3 | 22121022020221211002020222 |
4 | 203113013112220131323 |
5 | 304303120241334042 |
6 | 5100154353210255 |
7 | 340363456504415 |
oct | 43270726503573 |
9 | 8538227732228 |
10 | 2430001121147 |
11 | 857615312586 |
12 | 332b4a56098b |
13 | 1481c056abb2 |
14 | 858812ad9b5 |
15 | 433236722d2 |
hex | 235c75a877b |
2430001121147 has 2 divisors, whose sum is σ = 2430001121148. Its totient is φ = 2430001121146.
The previous prime is 2430001121099. The next prime is 2430001121153. The reversal of 2430001121147 is 7411211000342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2430001121147 - 228 = 2429732685691 is a prime.
It is not a weakly prime, because it can be changed into another prime (2430001121167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1215000560573 + 1215000560574.
It is an arithmetic number, because the mean of its divisors is an integer number (1215000560574).
Almost surely, 22430001121147 is an apocalyptic number.
2430001121147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2430001121147 is an equidigital number, since it uses as much as digits as its factorization.
2430001121147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 2430001121147 its reverse (7411211000342), we get a palindrome (9841212121489).
The spelling of 2430001121147 in words is "two trillion, four hundred thirty billion, one million, one hundred twenty-one thousand, one hundred forty-seven".
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