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243111504332 = 2276179865803
BaseRepresentation
bin1110001001101010010…
…0110010100111001100
3212020111212012000112002
43202122210302213030
512440343021114312
6303403415131432
723364346456004
oct3423244624714
9766455160462
10243111504332
1194115119524
123b149673b78
1319c04bc6c58
14baa39dd004
1564cd1c84c2
hex389a9329cc

243111504332 has 12 divisors (see below), whose sum is σ = 426004198536. Its totient is φ = 121396019040.

The previous prime is 243111504299. The next prime is 243111504341. The reversal of 243111504332 is 233405111342.

243111504332 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 243111504295 and 243111504304.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39929858 + ... + 39935945.

It is an arithmetic number, because the mean of its divisors is an integer number (35500349878).

Almost surely, 2243111504332 is an apocalyptic number.

It is an amenable number.

243111504332 is a deficient number, since it is larger than the sum of its proper divisors (182892694204).

243111504332 is a wasteful number, since it uses less digits than its factorization.

243111504332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79866568 (or 79866566 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 243111504332 its reverse (233405111342), we get a palindrome (476516615674).

The spelling of 243111504332 in words is "two hundred forty-three billion, one hundred eleven million, five hundred four thousand, three hundred thirty-two".

Divisors: 1 2 4 761 1522 3044 79865803 159731606 319463212 60777876083 121555752166 243111504332