243113300433 has 6 divisors (see below), whose sum is σ = 351163656194. Its totient is φ = 162075533616.

The previous prime is 243113300377. The next prime is 243113300467. The reversal of 243113300433 is 334003311342.

243113300433 is a `hidden beast` number, since 2 + 4 + 311 + 3 + 300 + 43 + 3 = 666.

243113300433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 217073991744 + 26039308689 = 465912^2 + 161367^2 .

It is not a de Polignac number, because 243113300433 - 2¹⁷ = 243113169361 is a prime.

It is a super-2 number, since 2×243113300433² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243113300397 and 243113300406.

It is not an unprimeable number, because it can be changed into a prime (243113300533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13506294460 + ... + 13506294477.

Almost surely, 2^243113300433 is an apocalyptic number.

It is an amenable number.

243113300433 is a deficient number, since it is larger than the sum of its proper divisors (108050355761).

243113300433 is a wasteful number, since it uses less digits than its factorization.

243113300433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27012588943 (or 27012588940 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 27.

Adding to 243113300433 its reverse (334003311342), we get a palindrome (577116611775).

The spelling of 243113300433 in words is "two hundred forty-three billion, one hundred thirteen million, three hundred thousand, four hundred thirty-three".