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243113454011 = 702493460739
BaseRepresentation
bin1110001001101010110…
…0001110100110111011
3212020111222212001222102
43202122230032212323
512440344021012021
6303403525014015
723364402156131
oct3423254164673
9766458761872
10243113454011
119411623032a
123b14a25430b
1319c0542a4cc
14baa3d89751
1564cd46100b
hex389ab0e9bb

243113454011 has 4 divisors (see below), whose sum is σ = 243116985000. Its totient is φ = 243109923024.

The previous prime is 243113453963. The next prime is 243113454047. The reversal of 243113454011 is 110454311342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 243113454011 - 234 = 225933584827 is a prime.

It is a super-2 number, since 2×2431134540112 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (243113454061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1660121 + ... + 1800618.

It is an arithmetic number, because the mean of its divisors is an integer number (60779246250).

Almost surely, 2243113454011 is an apocalyptic number.

243113454011 is a deficient number, since it is larger than the sum of its proper divisors (3530989).

243113454011 is an equidigital number, since it uses as much as digits as its factorization.

243113454011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3530988.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 243113454011 its reverse (110454311342), we get a palindrome (353567765353).

The spelling of 243113454011 in words is "two hundred forty-three billion, one hundred thirteen million, four hundred fifty-four thousand, eleven".

Divisors: 1 70249 3460739 243113454011