Base | Representation |
---|---|
bin | 100011011000001111000… |
… | …001000011011100001011 |
3 | 22121102100202011101201200 |
4 | 203120033001003130023 |
5 | 304313101034032021 |
6 | 5100513542515243 |
7 | 340435326063525 |
oct | 43301701033413 |
9 | 8542322141650 |
10 | 2431203424011 |
11 | 858081a5150a |
12 | 333225135b23 |
13 | 14835268a5cb |
14 | 85956c3ca15 |
15 | 43393eb5126 |
hex | 2360f04370b |
2431203424011 has 12 divisors (see below), whose sum is σ = 3512408910192. Its totient is φ = 1620492760656.
The previous prime is 2431203424003. The next prime is 2431203424093. The reversal of 2431203424011 is 1104243021342.
2431203424011 is a `hidden beast` number, since 2 + 4 + 31 + 203 + 424 + 0 + 1 + 1 = 666.
It is not a de Polignac number, because 2431203424011 - 23 = 2431203424003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2431203424211) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 25743751 + ... + 25838016.
It is an arithmetic number, because the mean of its divisors is an integer number (292700742516).
Almost surely, 22431203424011 is an apocalyptic number.
2431203424011 is a deficient number, since it is larger than the sum of its proper divisors (1081205486181).
2431203424011 is a wasteful number, since it uses less digits than its factorization.
2431203424011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51587010 (or 51587007 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 2431203424011 its reverse (1104243021342), we get a palindrome (3535446445353).
The spelling of 2431203424011 in words is "two trillion, four hundred thirty-one billion, two hundred three million, four hundred twenty-four thousand, eleven".
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