Base | Representation |
---|---|
bin | 1110001001101100100… |
… | …1111100110100000001 |
3 | 212020112112111220210220 |
4 | 3202123021330310001 |
5 | 12440403014323231 |
6 | 303404404013253 |
7 | 23364525326514 |
oct | 3423311746401 |
9 | 766475456726 |
10 | 243121245441 |
11 | 9411a672128 |
12 | 3b150991229 |
13 | 19c06c27a19 |
14 | baa5016d7b |
15 | 64cde9e896 |
hex | 389b27cd01 |
243121245441 has 4 divisors (see below), whose sum is σ = 324161660592. Its totient is φ = 162080830292.
The previous prime is 243121245421. The next prime is 243121245449. The reversal of 243121245441 is 144542121342.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 243121245441 - 210 = 243121244417 is a prime.
It is not an unprimeable number, because it can be changed into a prime (243121245449) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40520207571 + ... + 40520207576.
It is an arithmetic number, because the mean of its divisors is an integer number (81040415148).
Almost surely, 2243121245441 is an apocalyptic number.
It is an amenable number.
243121245441 is a deficient number, since it is larger than the sum of its proper divisors (81040415151).
243121245441 is an equidigital number, since it uses as much as digits as its factorization.
243121245441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81040415150.
The product of its digits is 30720, while the sum is 33.
Adding to 243121245441 its reverse (144542121342), we get a palindrome (387663366783).
The spelling of 243121245441 in words is "two hundred forty-three billion, one hundred twenty-one million, two hundred forty-five thousand, four hundred forty-one".
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