2431214331041 has 4 divisors (see below), whose sum is σ = 2431235323284. Its totient is φ = 2431193338800.

The previous prime is 2431214330969. The next prime is 2431214331059. The reversal of 2431214331041 is 1401334121342.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 77662542400 + 2353551788641 = 278680^2 + 1534129^2 .

It is a cyclic number.

It is not a de Polignac number, because 2431214331041 - 2²² = 2431210136737 is a prime.

It is a super-2 number, since 2×2431214331041² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2431214330995 and 2431214331013.

It is not an unprimeable number, because it can be changed into a prime (2431214331061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10321430 + ... + 10554351.

It is an arithmetic number, because the mean of its divisors is an integer number (607808830821).

Almost surely, 2^{2431214331041} is an apocalyptic number.

It is an amenable number.

2431214331041 is a deficient number, since it is larger than the sum of its proper divisors (20992243).

2431214331041 is a wasteful number, since it uses less digits than its factorization.

2431214331041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20992242.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 2431214331041 its reverse (1401334121342), we get a palindrome (3832548452383).

The spelling of 2431214331041 in words is "two trillion, four hundred thirty-one billion, two hundred fourteen million, three hundred thirty-one thousand, forty-one".