Base | Representation |
---|---|
bin | 1110001001101111001… |
… | …1010111101100000011 |
3 | 212020120021221120011112 |
4 | 3202123303113230003 |
5 | 12440413304302202 |
6 | 303405432433535 |
7 | 23365016531453 |
oct | 3423363275403 |
9 | 766507846145 |
10 | 243132103427 |
11 | 94125808974 |
12 | 3b1545488ab |
13 | 19c09259c75 |
14 | baa6641d63 |
15 | 64cede6b52 |
hex | 389bcd7b03 |
243132103427 has 2 divisors, whose sum is σ = 243132103428. Its totient is φ = 243132103426.
The previous prime is 243132103351. The next prime is 243132103499. The reversal of 243132103427 is 724301231342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 243132103427 - 216 = 243132037891 is a prime.
It is a super-2 number, since 2×2431321034272 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 243132103393 and 243132103402.
It is not a weakly prime, because it can be changed into another prime (243132103127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121566051713 + 121566051714.
It is an arithmetic number, because the mean of its divisors is an integer number (121566051714).
Almost surely, 2243132103427 is an apocalyptic number.
243132103427 is a deficient number, since it is larger than the sum of its proper divisors (1).
243132103427 is an equidigital number, since it uses as much as digits as its factorization.
243132103427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 32.
Adding to 243132103427 its reverse (724301231342), we get a palindrome (967433334769).
The spelling of 243132103427 in words is "two hundred forty-three billion, one hundred thirty-two million, one hundred three thousand, four hundred twenty-seven".
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