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243132142193 is a prime number
BaseRepresentation
bin1110001001101111001…
…1100001001001110001
3212020120022000112100022
43202123303201021301
512440413312022233
6303405433333225
723365020052463
oct3423363411161
9766508015308
10243132142193
1194125835006
123b154567215
1319c092717c5
14baa6652133
1564cee03398
hex389bce1271

243132142193 has 2 divisors, whose sum is σ = 243132142194. Its totient is φ = 243132142192.

The previous prime is 243132142171. The next prime is 243132142207. The reversal of 243132142193 is 391241231342.

243132142193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 182924723809 + 60207418384 = 427697^2 + 245372^2 .

It is a cyclic number.

It is not a de Polignac number, because 243132142193 - 228 = 242863706737 is a prime.

It is a super-2 number, since 2×2431321421932 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (243132142103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121566071096 + 121566071097.

It is an arithmetic number, because the mean of its divisors is an integer number (121566071097).

Almost surely, 2243132142193 is an apocalyptic number.

It is an amenable number.

243132142193 is a deficient number, since it is larger than the sum of its proper divisors (1).

243132142193 is an equidigital number, since it uses as much as digits as its factorization.

243132142193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 35.

The spelling of 243132142193 in words is "two hundred forty-three billion, one hundred thirty-two million, one hundred forty-two thousand, one hundred ninety-three".