Base | Representation |
---|---|
bin | 1110001001101111001… |
… | …1110010011110101001 |
3 | 212020120022011010200202 |
4 | 3202123303302132221 |
5 | 12440413321310121 |
6 | 303405435041545 |
7 | 23365020466415 |
oct | 3423363623651 |
9 | 766508133622 |
10 | 243132213161 |
11 | 94125883362 |
12 | 3b1545a02b5 |
13 | 19c09297bb6 |
14 | baa666dd45 |
15 | 64cee1940b |
hex | 389bcf27a9 |
243132213161 has 2 divisors, whose sum is σ = 243132213162. Its totient is φ = 243132213160.
The previous prime is 243132213143. The next prime is 243132213257. The reversal of 243132213161 is 161312231342.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 174556840000 + 68575373161 = 417800^2 + 261869^2 .
It is a cyclic number.
It is not a de Polignac number, because 243132213161 - 214 = 243132196777 is a prime.
It is a super-2 number, since 2×2431322131612 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (243132210161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121566106580 + 121566106581.
It is an arithmetic number, because the mean of its divisors is an integer number (121566106581).
Almost surely, 2243132213161 is an apocalyptic number.
It is an amenable number.
243132213161 is a deficient number, since it is larger than the sum of its proper divisors (1).
243132213161 is an equidigital number, since it uses as much as digits as its factorization.
243132213161 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 29.
The spelling of 243132213161 in words is "two hundred forty-three billion, one hundred thirty-two million, two hundred thirteen thousand, one hundred sixty-one".
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