Base | Representation |
---|---|
bin | 1110001001110001000… |
… | …1111101100111110001 |
3 | 212020120212001000010020 |
4 | 3202130101331213301 |
5 | 12440422332414441 |
6 | 303410320354053 |
7 | 23365144642500 |
oct | 3423421754761 |
9 | 766525030106 |
10 | 243140123121 |
11 | 9412a296215 |
12 | 3b157175929 |
13 | 19c0ab0734c |
14 | baa772c837 |
15 | 64d097ce66 |
hex | 389c47d9f1 |
243140123121 has 12 divisors (see below), whose sum is σ = 377115293232. Its totient is φ = 138937213128.
The previous prime is 243140123119. The next prime is 243140123159. The reversal of 243140123121 is 121321041342.
It is not a de Polignac number, because 243140123121 - 21 = 243140123119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 243140123091 and 243140123100.
It is not an unprimeable number, because it can be changed into a prime (243140123101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 827007075 + ... + 827007368.
It is an arithmetic number, because the mean of its divisors is an integer number (31426274436).
Almost surely, 2243140123121 is an apocalyptic number.
243140123121 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
243140123121 is a deficient number, since it is larger than the sum of its proper divisors (133975170111).
243140123121 is a wasteful number, since it uses less digits than its factorization.
243140123121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1654014460 (or 1654014453 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 243140123121 its reverse (121321041342), we get a palindrome (364461164463).
The spelling of 243140123121 in words is "two hundred forty-three billion, one hundred forty million, one hundred twenty-three thousand, one hundred twenty-one".
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