Base | Representation |
---|---|
bin | 1110001001110001111… |
… | …0100111100000011011 |
3 | 212020121002021112120211 |
4 | 3202130132213200123 |
5 | 12440424210043121 |
6 | 303410515431551 |
7 | 23365215100054 |
oct | 3423436474033 |
9 | 766532245524 |
10 | 243143440411 |
11 | 94131151583 |
12 | 3b1582b55b7 |
13 | 19c0b6c9241 |
14 | baa7d5372b |
15 | 64d0dd5ce1 |
hex | 389c7a781b |
243143440411 has 4 divisors (see below), whose sum is σ = 243684963000. Its totient is φ = 242601917824.
The previous prime is 243143440369. The next prime is 243143440447. The reversal of 243143440411 is 114044341342.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 243143440411 - 27 = 243143440283 is a prime.
It is a super-2 number, since 2×2431434404112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (243143440471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 270760621 + ... + 270761518.
It is an arithmetic number, because the mean of its divisors is an integer number (60921240750).
Almost surely, 2243143440411 is an apocalyptic number.
243143440411 is a deficient number, since it is larger than the sum of its proper divisors (541522589).
243143440411 is an equidigital number, since it uses as much as digits as its factorization.
243143440411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 541522588.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 243143440411 its reverse (114044341342), we get a palindrome (357187781753).
The spelling of 243143440411 in words is "two hundred forty-three billion, one hundred forty-three million, four hundred forty thousand, four hundred eleven".
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