Base | Representation |
---|---|
bin | 1011000011101001011000… |
… | …01111010000110010111001 |
3 | 10012002110002221100112101102 |
4 | 11201310230033100302321 |
5 | 11141332200311423423 |
6 | 123413541230301145 |
7 | 5056445160313466 |
oct | 541645417206271 |
9 | 105073087315342 |
10 | 24314552061113 |
11 | 782481a839896 |
12 | 28883a63577b5 |
13 | 1074b109cc602 |
14 | 600b8b24066d |
15 | 2c2725d31c28 |
hex | 161d2c3d0cb9 |
24314552061113 has 4 divisors (see below), whose sum is σ = 24314573711220. Its totient is φ = 24314530411008.
The previous prime is 24314552061089. The next prime is 24314552061133. The reversal of 24314552061113 is 31116025541342.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3719991697984 + 20594560363129 = 1928728^2 + 4538123^2 .
It is a cyclic number.
It is not a de Polignac number, because 24314552061113 - 244 = 6722366016697 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (24314552061133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9042620 + ... + 11419197.
It is an arithmetic number, because the mean of its divisors is an integer number (6078643427805).
Almost surely, 224314552061113 is an apocalyptic number.
It is an amenable number.
24314552061113 is a deficient number, since it is larger than the sum of its proper divisors (21650107).
24314552061113 is a wasteful number, since it uses less digits than its factorization.
24314552061113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21650106.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 24314552061113 in words is "twenty-four trillion, three hundred fourteen billion, five hundred fifty-two million, sixty-one thousand, one hundred thirteen".
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