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24314552061113 = 118828920461817
BaseRepresentation
bin1011000011101001011000…
…01111010000110010111001
310012002110002221100112101102
411201310230033100302321
511141332200311423423
6123413541230301145
75056445160313466
oct541645417206271
9105073087315342
1024314552061113
11782481a839896
1228883a63577b5
131074b109cc602
14600b8b24066d
152c2725d31c28
hex161d2c3d0cb9

24314552061113 has 4 divisors (see below), whose sum is σ = 24314573711220. Its totient is φ = 24314530411008.

The previous prime is 24314552061089. The next prime is 24314552061133. The reversal of 24314552061113 is 31116025541342.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3719991697984 + 20594560363129 = 1928728^2 + 4538123^2 .

It is a cyclic number.

It is not a de Polignac number, because 24314552061113 - 244 = 6722366016697 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (24314552061133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9042620 + ... + 11419197.

It is an arithmetic number, because the mean of its divisors is an integer number (6078643427805).

Almost surely, 224314552061113 is an apocalyptic number.

It is an amenable number.

24314552061113 is a deficient number, since it is larger than the sum of its proper divisors (21650107).

24314552061113 is a wasteful number, since it uses less digits than its factorization.

24314552061113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21650106.

The product of its (nonzero) digits is 86400, while the sum is 38.

The spelling of 24314552061113 in words is "twenty-four trillion, three hundred fourteen billion, five hundred fifty-two million, sixty-one thousand, one hundred thirteen".

Divisors: 1 1188289 20461817 24314552061113