Base | Representation |
---|---|
bin | 100011011001011111010… |
… | …111010100111011110001 |
3 | 22121112211200200201011222 |
4 | 203121133113110323301 |
5 | 304323331132040423 |
6 | 5101255415314425 |
7 | 340513615036604 |
oct | 43313727247361 |
9 | 8545750621158 |
10 | 2432551440113 |
11 | 858703964a03 |
12 | 33354067ba15 |
13 | 148508a37982 |
14 | 85a43c9c33b |
15 | 434224dc3c8 |
hex | 2365f5d4ef1 |
2432551440113 has 4 divisors (see below), whose sum is σ = 2432614324080. Its totient is φ = 2432488556148.
The previous prime is 2432551440107. The next prime is 2432551440149. The reversal of 2432551440113 is 3110441552342.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2432551440113 - 26 = 2432551440049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2432551440103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31383923 + ... + 31461336.
It is an arithmetic number, because the mean of its divisors is an integer number (608153581020).
Almost surely, 22432551440113 is an apocalyptic number.
It is an amenable number.
2432551440113 is a deficient number, since it is larger than the sum of its proper divisors (62883967).
2432551440113 is an equidigital number, since it uses as much as digits as its factorization.
2432551440113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62883966.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 2432551440113 its reverse (3110441552342), we get a palindrome (5542992992455).
The spelling of 2432551440113 in words is "two trillion, four hundred thirty-two billion, five hundred fifty-one million, four hundred forty thousand, one hundred thirteen".
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