Base | Representation |
---|---|
bin | 1110001010011100000… |
… | …1011101001110111011 |
3 | 212021001102011020210022 |
4 | 3202213001131032323 |
5 | 12441310002024111 |
6 | 303440235241055 |
7 | 23402463545324 |
oct | 3424701351673 |
9 | 767042136708 |
10 | 243320345531 |
11 | 94211a9aa5a |
12 | 3b1a75a918b |
13 | 19c39258523 |
14 | bac364344b |
15 | 64e16cc2db |
hex | 38a705d3bb |
243320345531 has 2 divisors, whose sum is σ = 243320345532. Its totient is φ = 243320345530.
The previous prime is 243320345509. The next prime is 243320345539. The reversal of 243320345531 is 135543023342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 243320345531 - 210 = 243320344507 is a prime.
It is a super-2 number, since 2×2433203455312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 243320345491 and 243320345500.
It is not a weakly prime, because it can be changed into another prime (243320345539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121660172765 + 121660172766.
It is an arithmetic number, because the mean of its divisors is an integer number (121660172766).
Almost surely, 2243320345531 is an apocalyptic number.
243320345531 is a deficient number, since it is larger than the sum of its proper divisors (1).
243320345531 is an equidigital number, since it uses as much as digits as its factorization.
243320345531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 243320345531 its reverse (135543023342), we get a palindrome (378863368873).
The spelling of 243320345531 in words is "two hundred forty-three billion, three hundred twenty million, three hundred forty-five thousand, five hundred thirty-one".
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