243434123131 has 4 divisors (see below), whose sum is σ = 243678290752. Its totient is φ = 243189955512.

The previous prime is 243434123123. The next prime is 243434123147. The reversal of 243434123131 is 131321434342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 243434123131 - 2³ = 243434123123 is a prime.

It is a super-3 number, since 3×243434123131³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243434123093 and 243434123102.

It is not an unprimeable number, because it can be changed into a prime (243434123171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122082315 + ... + 122084308.

It is an arithmetic number, because the mean of its divisors is an integer number (60919572688).

Almost surely, 2^243434123131 is an apocalyptic number.

243434123131 is a deficient number, since it is larger than the sum of its proper divisors (244167621).

243434123131 is an equidigital number, since it uses as much as digits as its factorization.

243434123131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 244167620.

The product of its digits is 20736, while the sum is 31.

Adding to 243434123131 its reverse (131321434342), we get a palindrome (374755557473).

The spelling of 243434123131 in words is "two hundred forty-three billion, four hundred thirty-four million, one hundred twenty-three thousand, one hundred thirty-one".