Base | Representation |
---|---|
bin | 1110001011010000100… |
… | …0010011011001000010 |
3 | 212021121201221020211022 |
4 | 3202310020103121002 |
5 | 12442232300302114 |
6 | 303514132345442 |
7 | 23411103626663 |
oct | 3426410233102 |
9 | 767551836738 |
10 | 243540244034 |
11 | 94315133a5a |
12 | 3b249175282 |
13 | 19c7298b999 |
14 | bb0492536a |
15 | 6505b6748e |
hex | 38b4213642 |
243540244034 has 4 divisors (see below), whose sum is σ = 365310366054. Its totient is φ = 121770122016.
The previous prime is 243540244033. The next prime is 243540244061. The reversal of 243540244034 is 430442045342.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 159158708809 + 84381535225 = 398947^2 + 290485^2 .
It is a super-3 number, since 3×2435402440343 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 243540243985 and 243540244003.
It is not an unprimeable number, because it can be changed into a prime (243540244033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60885061007 + ... + 60885061010.
Almost surely, 2243540244034 is an apocalyptic number.
243540244034 is a deficient number, since it is larger than the sum of its proper divisors (121770122020).
243540244034 is a wasteful number, since it uses less digits than its factorization.
243540244034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 121770122019.
The product of its (nonzero) digits is 184320, while the sum is 35.
Adding to 243540244034 its reverse (430442045342), we get a palindrome (673982289376).
The spelling of 243540244034 in words is "two hundred forty-three billion, five hundred forty million, two hundred forty-four thousand, thirty-four".
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