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243540244034 = 2121770122017
BaseRepresentation
bin1110001011010000100…
…0010011011001000010
3212021121201221020211022
43202310020103121002
512442232300302114
6303514132345442
723411103626663
oct3426410233102
9767551836738
10243540244034
1194315133a5a
123b249175282
1319c7298b999
14bb0492536a
156505b6748e
hex38b4213642

243540244034 has 4 divisors (see below), whose sum is σ = 365310366054. Its totient is φ = 121770122016.

The previous prime is 243540244033. The next prime is 243540244061. The reversal of 243540244034 is 430442045342.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 159158708809 + 84381535225 = 398947^2 + 290485^2 .

It is a super-3 number, since 3×2435402440343 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 243540243985 and 243540244003.

It is not an unprimeable number, because it can be changed into a prime (243540244033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60885061007 + ... + 60885061010.

Almost surely, 2243540244034 is an apocalyptic number.

243540244034 is a deficient number, since it is larger than the sum of its proper divisors (121770122020).

243540244034 is a wasteful number, since it uses less digits than its factorization.

243540244034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121770122019.

The product of its (nonzero) digits is 184320, while the sum is 35.

Adding to 243540244034 its reverse (430442045342), we get a palindrome (673982289376).

The spelling of 243540244034 in words is "two hundred forty-three billion, five hundred forty million, two hundred forty-four thousand, thirty-four".

Divisors: 1 2 121770122017 243540244034