Base | Representation |
---|---|
bin | 100011100000100011111… |
… | …011110010110100011101 |
3 | 22122021102212000000200111 |
4 | 203200203323302310131 |
5 | 304434403420120331 |
6 | 5104553052530021 |
7 | 341203023223345 |
oct | 43404373626435 |
9 | 8567385000614 |
10 | 2440144301341 |
11 | 86094a930a2a |
12 | 334abb480911 |
13 | 149148b0a076 |
14 | 86164463d25 |
15 | 43718db3db1 |
hex | 23823ef2d1d |
2440144301341 has 16 divisors (see below), whose sum is σ = 2606820854400. Its totient is φ = 2277537550848.
The previous prime is 2440144301327. The next prime is 2440144301423. The reversal of 2440144301341 is 1431034410442.
It is a cyclic number.
It is not a de Polignac number, because 2440144301341 - 29 = 2440144300829 is a prime.
It is a super-2 number, since 2×24401443013412 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2440142301341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3044256 + ... + 3761353.
It is an arithmetic number, because the mean of its divisors is an integer number (162926303400).
Almost surely, 22440144301341 is an apocalyptic number.
It is an amenable number.
2440144301341 is a deficient number, since it is larger than the sum of its proper divisors (166676553059).
2440144301341 is a wasteful number, since it uses less digits than its factorization.
2440144301341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6805908.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 2440144301341 its reverse (1431034410442), we get a palindrome (3871178711783).
The spelling of 2440144301341 in words is "two trillion, four hundred forty billion, one hundred forty-four million, three hundred one thousand, three hundred forty-one".
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