Base | Representation |
---|---|
bin | 1011000110010010011100… |
… | …00001010001111010000011 |
3 | 10012102010101020022202112021 |
4 | 11203021032001101322003 |
5 | 11144324040130243321 |
6 | 123523351315142311 |
7 | 5066140260565162 |
oct | 543111601217203 |
9 | 105363336282467 |
10 | 24405313134211 |
11 | 785a265023409 |
12 | 28a1ab5ba4997 |
13 | 10805463c54a9 |
14 | 60531b2533d9 |
15 | 2c4c88de6941 |
hex | 16324e051e83 |
24405313134211 has 2 divisors, whose sum is σ = 24405313134212. Its totient is φ = 24405313134210.
The previous prime is 24405313134121. The next prime is 24405313134217. The reversal of 24405313134211 is 11243131350442.
Together with previous prime (24405313134121) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 24405313134211 - 29 = 24405313133699 is a prime.
It is not a weakly prime, because it can be changed into another prime (24405313134217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12202656567105 + 12202656567106.
It is an arithmetic number, because the mean of its divisors is an integer number (12202656567106).
Almost surely, 224405313134211 is an apocalyptic number.
24405313134211 is a deficient number, since it is larger than the sum of its proper divisors (1).
24405313134211 is an equidigital number, since it uses as much as digits as its factorization.
24405313134211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 24405313134211 its reverse (11243131350442), we get a palindrome (35648444484653).
The spelling of 24405313134211 in words is "twenty-four trillion, four hundred five billion, three hundred thirteen million, one hundred thirty-four thousand, two hundred eleven".
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