Base | Representation |
---|---|
bin | 100011100001011101101… |
… | …011001010011010001011 |
3 | 22122100221100211000220221 |
4 | 203201131223022122023 |
5 | 304443344413120133 |
6 | 5105233135530511 |
7 | 341236025211205 |
oct | 43413553123213 |
9 | 8570840730827 |
10 | 2441113020043 |
11 | 8612a77296a5 |
12 | 33512b989a37 |
13 | 149271713cb9 |
14 | 86216d8b775 |
15 | 43773e66a2d |
hex | 2385daca68b |
2441113020043 has 2 divisors, whose sum is σ = 2441113020044. Its totient is φ = 2441113020042.
The previous prime is 2441113020037. The next prime is 2441113020089. The reversal of 2441113020043 is 3400203111442.
2441113020043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2441113020043 - 229 = 2440576149131 is a prime.
It is a super-2 number, since 2×24411130200432 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2441113020013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1220556510021 + 1220556510022.
It is an arithmetic number, because the mean of its divisors is an integer number (1220556510022).
Almost surely, 22441113020043 is an apocalyptic number.
2441113020043 is a deficient number, since it is larger than the sum of its proper divisors (1).
2441113020043 is an equidigital number, since it uses as much as digits as its factorization.
2441113020043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2441113020043 its reverse (3400203111442), we get a palindrome (5841316131485).
The spelling of 2441113020043 in words is "two trillion, four hundred forty-one billion, one hundred thirteen million, twenty thousand, forty-three".
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