Base | Representation |
---|---|
bin | 1011000111000011000110… |
… | …10011110011000111011011 |
3 | 10012111121211001211212011112 |
4 | 11203201203103303013123 |
5 | 11200241042132123024 |
6 | 123543352035050535 |
7 | 5101053601342262 |
oct | 543414323630733 |
9 | 105447731755145 |
10 | 24431440114139 |
11 | 786a352022103 |
12 | 28a6b87a40a4b |
13 | 1082b4b267b26 |
14 | 6066b915d5d9 |
15 | 2c57b79ce00e |
hex | 1638634f31db |
24431440114139 has 2 divisors, whose sum is σ = 24431440114140. Its totient is φ = 24431440114138.
The previous prime is 24431440114121. The next prime is 24431440114187. The reversal of 24431440114139 is 93141104413442.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-24431440114139 is a prime.
It is a super-3 number, since 3×244314401141393 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 24431440114096 and 24431440114105.
It is not a weakly prime, because it can be changed into another prime (24431440114639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12215720057069 + 12215720057070.
It is an arithmetic number, because the mean of its divisors is an integer number (12215720057070).
Almost surely, 224431440114139 is an apocalyptic number.
24431440114139 is a deficient number, since it is larger than the sum of its proper divisors (1).
24431440114139 is an equidigital number, since it uses as much as digits as its factorization.
24431440114139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 41.
The spelling of 24431440114139 in words is "twenty-four trillion, four hundred thirty-one billion, four hundred forty million, one hundred fourteen thousand, one hundred thirty-nine".
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