Base | Representation |
---|---|
bin | 100011100011100110001… |
… | …010110010111110101001 |
3 | 22122120211221211210011001 |
4 | 203203212022302332221 |
5 | 310013042132422212 |
6 | 5110252302235001 |
7 | 341346542636455 |
oct | 43434612627651 |
9 | 8576757753131 |
10 | 2443403014057 |
11 | 862272336035 |
12 | 33566a885a61 |
13 | 149547c94945 |
14 | 86393173665 |
15 | 4385a00d657 |
hex | 238e62b2fa9 |
2443403014057 has 2 divisors, whose sum is σ = 2443403014058. Its totient is φ = 2443403014056.
The previous prime is 2443403013937. The next prime is 2443403014061. The reversal of 2443403014057 is 7504103043442.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1667974833001 + 775428181056 = 1291501^2 + 880584^2 .
It is a cyclic number.
It is not a de Polignac number, because 2443403014057 - 27 = 2443403013929 is a prime.
It is not a weakly prime, because it can be changed into another prime (2443403014067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221701507028 + 1221701507029.
It is an arithmetic number, because the mean of its divisors is an integer number (1221701507029).
Almost surely, 22443403014057 is an apocalyptic number.
It is an amenable number.
2443403014057 is a deficient number, since it is larger than the sum of its proper divisors (1).
2443403014057 is an equidigital number, since it uses as much as digits as its factorization.
2443403014057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 161280, while the sum is 37.
Adding to 2443403014057 its reverse (7504103043442), we get a palindrome (9947506057499).
The spelling of 2443403014057 in words is "two trillion, four hundred forty-three billion, four hundred three million, fourteen thousand, fifty-seven".
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