Base | Representation |
---|---|
bin | 100011100100010111000… |
… | …111000001111000110011 |
3 | 22122122222011212210012202 |
4 | 203210113013001320303 |
5 | 310021232333011011 |
6 | 5110505553213415 |
7 | 341406103065536 |
oct | 43442707017063 |
9 | 8578864783182 |
10 | 2444224110131 |
11 | 862653875731 |
12 | 33585986126b |
13 | 149649122acb |
14 | 86430230a1d |
15 | 438a715123b |
hex | 239171c1e33 |
2444224110131 has 2 divisors, whose sum is σ = 2444224110132. Its totient is φ = 2444224110130.
The previous prime is 2444224110049. The next prime is 2444224110151. The reversal of 2444224110131 is 1310114224442.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2444224110131 is a prime.
It is a super-2 number, since 2×24442241101312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2444224110094 and 2444224110103.
It is not a weakly prime, because it can be changed into another prime (2444224110151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1222112055065 + 1222112055066.
It is an arithmetic number, because the mean of its divisors is an integer number (1222112055066).
Almost surely, 22444224110131 is an apocalyptic number.
2444224110131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2444224110131 is an equidigital number, since it uses as much as digits as its factorization.
2444224110131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 2444224110131 its reverse (1310114224442), we get a palindrome (3754338334573).
The spelling of 2444224110131 in words is "two trillion, four hundred forty-four billion, two hundred twenty-four million, one hundred ten thousand, one hundred thirty-one".
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