Base | Representation |
---|---|
bin | 1110001110100111111… |
… | …1111011110101001011 |
3 | 212100221201112211102211 |
4 | 3203221333323311023 |
5 | 13001110132120133 |
6 | 304143535405551 |
7 | 23442356613316 |
oct | 3435177736513 |
9 | 770851484384 |
10 | 244444020043 |
11 | 94739305283 |
12 | 3b45b9838b7 |
13 | 1a087ca7ca2 |
14 | bb8c98597d |
15 | 655a18cbcd |
hex | 38e9ffbd4b |
244444020043 has 4 divisors (see below), whose sum is σ = 244469926720. Its totient is φ = 244418113368.
The previous prime is 244444019969. The next prime is 244444020077. The reversal of 244444020043 is 340020444442.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 244444020043 - 29 = 244444019531 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 244444019987 and 244444020014.
It is not an unprimeable number, because it can be changed into a prime (244444020083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12939180 + ... + 12958057.
It is an arithmetic number, because the mean of its divisors is an integer number (61117481680).
Almost surely, 2244444020043 is an apocalyptic number.
244444020043 is a deficient number, since it is larger than the sum of its proper divisors (25906677).
244444020043 is an equidigital number, since it uses as much as digits as its factorization.
244444020043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25906676.
The product of its (nonzero) digits is 49152, while the sum is 31.
Adding to 244444020043 its reverse (340020444442), we get a palindrome (584464464485).
The spelling of 244444020043 in words is "two hundred forty-four billion, four hundred forty-four million, twenty thousand, forty-three".
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